MHT CET 2026 Physics question
In a biprism experiment, fifth dark fringe is obtained at a point. A thin transparent film of refractive index '' is placed in one of the interfering paths. Now 7<sup>th</sup> bright fringe is obtained at the same point. If '' is the wavelength of light used, the thickness of film is equal to
Answer: (D)
Solution
At the given point the path difference initially corresponds to the 5th dark fringe: with , i.e. . After inserting the film of thickness in one path, an extra optical path is introduced and the same point
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