MHT CET 2025 Physics question
A string of mass 0.1 kgm has length 0.9 m. It is fixed at both ends and stretched such that it has a tension of 40 N. The string vibrates in three segments with amplitude 0.3 cm. The amplitude (maximum) of the particle velocity is (in m/s)
Answer: (C)
Solution
The linear mass density is kg/m, so the wave speed is m/s. Three segments means the third harmonic: m, so Hz and $ω=2π
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