For stationary wave, y = 12 ( x 10 ) (36 t) ,cm, the distance between node and the successive antinode is

MHT CET 2026 Physics question

For stationary wave, , the distance between node and the successive antinode is

Answer: (D)

Compare with : cm. Since , cm. A node and the next antinode are separated by a quarter wavelength:

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Question ID VK-100829