MHT CET 2026 Physics question
In a single slit diffraction pattern, the distance between the plane of the slit and the screen is 1.4 m. The width of the slit is 0.66 mm. The second maximum is formed at the distance of 2.8 mm from the center of the screen. The wavelength of light used is
Answer: (C)
Solution
In single-slit diffraction the th secondary maximum lies at , where is the slit width and the screen distance. For the second maximum : . Hence \dfrac{2a y_2}{5D}\dfrac10^{-3}$× 2.8×
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