MHT CET 2026 Physics question
A slab of material of dielectric constant K has the same area as the plates of a parallel plate capacitor but has a thickness (4/5) d, where d is the separation of the plates. The capacitance in the presence and absence of dielectric are C and respectively. The ratio () is
Answer: (C)
Solution
Without the slab . With a dielectric slab of thickness and constant inside a capacitor of plate separation : . Here , so \dfrac{t}{K}\dfrac{d}{5}\dfrac{4d}{5K}\dfrac${d(K +
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