MHT CET 2025 Mathematics question
A random variable X has the following probability distribution X: 0, 1, 2, 3, 4 P(X): k, 2k, 4k, 2k, k then the value of
Answer: (B)
Solution
The probabilities sum to 1: , so . Let and . Then . \mid\dfrac{P(A\cap B)}{P(B)}$ =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account