MHT CET 2025 Mathematics question
Not in JEE syllabus
In a triangle ABC, with usual notations if then
Answer: (A)
Solution
Use the cosine rule: , so ; ; . LHS \dfrac{2(b^2+c^2-a^2) + (c^2+a^2-b^2) + 2(a^2+b^2-c^2)}{2abc}\dfrac3b^2a^2$ +
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account