MHT CET 2026 Physics question
The self inductance of an air-core inductor (solenoid) is 0.03 mH. By introducing an iron core into inductor the self-inductance increases to 30 mH. The relative permeability of the core used is
Answer: (D)
Solution
For a solenoid , so with the same geometry . Hence \frac{L_{core}}{L_{air}}\frac{30\ mH}{0.03\ mH}$ =
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