MHT CET 2026 Physics question
The proton and -particle are accelerated through same potential difference. Then the ratio of the de-Broglie wavelength of proton and -particle is (mass of -particle is 4 times mass of proton, charge of -particle is 2 times charge of proton)
Answer: (D)
Solution
A charged particle accelerated through potential difference gains kinetic energy , so momentum and the de Broglie wavelength is . For the same : $ = {{m_α
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