MHT CET 2025 Mathematics question

Four defective oranges are accidentally mixed with sixteen good ones. Three oranges are drawn from the mixed lot. The probability distribution of defective oranges is

(A)X: 0, 1, 2, 3; P(X=x): 28/57, 8/95, 8/19, 1/285
(B)X: 0, 1, 2, 3; P(X=x): 28/57, 8/95, 1/285, 8/19
(C)X: 0, 1, 2, 3; P(X=x): 28/57, 8/95, 1/285, 8/19Correct
(D)X: 0, 1, 2, 3; P(X=x): 1/285, 8/95, 8/19, 28/57

Answer: (C)

Solution

Total oranges 20 (4 defective, 16 good), 3 drawn without replacement: total ways . . . .

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Question ID VK-102150