MHT CET 2025 Physics question
A body when projected at an angle '' with the horizontal reaches a maximum height 'H'. The time of flight of the body will be (g = acceleration due to gravity)
Answer: (C)
Solution
Maximum height . Time of flight \dfrac{2u\sinθ}{g}\dfrac{2\sqrt{2gH}}{g}$ =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account