MHT CET 2025 Chemistry question

What is the molar mass of third homologue of alkane series?

(A)40 g mol
(B)58 g mol
(C)44 g molCorrect
(D)46 g mol

Answer: (C)

Solution

The alkane homologous series has general formula and successive members differ by a unit (14 g mol). The members are methane (, 16), ethane (, 30), propane () ... The third homologue is

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Question ID VK-102507