MHT CET 2025 Physics question
A bob of mass 'm' is tied by a massless string whose other end is wound on a flywheel (disc) of radius 'R' and mass 'm'. When released from the rest, the bob starts falling vertically downwards. If the bob has covered a vertical distance 'h', then angular speed of wheel will be (There is no slipping between string and wheel, g - acceleration due to gravity)
Answer: (A)
Solution
By energy conservation the loss of potential energy of the bob equals the kinetic energy of the bob plus the rotational kinetic energy of the disc. With no slipping, , and for a disc. So \tfracmv^2\tfrac\tfracmR^2\tfracmR^2\tfrac$34
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