MHT CET 2025 Physics question

Physics Oscillations MHT CET 2025

Two simple pendulums have first (A) bob of mass 'M' and length 'L', second (B) of mass 'M' and length 'L'. M = M and L = 2L. If their total energies are same then the correct statement is

(A)amplitude of B is greater than amplitude of A.
(B)amplitude of B is smaller than amplitude of A.Correct
(C)amplitude of both will be same.
(D)amplitude of B is twice that of A.

Answer: (B)

Solution

For small oscillations a pendulum executes SHM with , and its total energy is (a = amplitude). With equal masses and equal energies this gives . Since ,

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Question ID VK-102617