The equation of the tangent to the curve y = be^ -x/a at the point where it crosses the Y axis is

MHT CET 2025 Mathematics question

The equation of the tangent to the curve at the point where it crosses the Y axis is

Answer: (A)

The curve crosses the Y-axis where : , so the point is . Differentiate: , so at the slope is . The tangent is \dfrac$

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Question ID VK-103054