MHT CET 2025 Mathematics question

Not in JEE syllabus

In a triangle ABC, with usual notations, (a + b + c) (a + b – c) = 3ab, then

Answer: (C)

Solution

(a+b+c)(a+b-c)=(a+b)^2-c^2=3ab\Rightarrow a^2+2ab+b^2-c^2=3ab\Rightarrow a^2+b^2-c^2=ab. By the cosine rule, $

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Question ID VK-103179