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MHT CET 2025 Physics question

PhysicsElectromagnetic InductionMHT CET 2025

Two inductors of 80 mH each are joined in parallel. The current passing through the combination is 2.1 A. The energy stored in this combination of inductors is

Answer: (C)

Solution

For inductors in parallel (no mutual inductance) , so mH H. Energy stored \dfrac{1}{2}$ = ×0.04×(2. = 0.02×4.41 =

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Question ID VK-103213