MHT CET 2025 Physics question
A point particle of mass 200 gram is executing S.H.M. of amplitude 0.2 m. When the particle passes through the mean position, its kinetic energy is 16 x 10 J. The equation of motion of this particle is (Initial phase of oscillation = )
Answer: (D)
Solution
At the mean position the kinetic energy is maximum: . With kg, m, J: \dfrac{2K_{max}}{mA^2}\dfrac{2×16×10^{-3}}{0.2×0.04}$ =
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