JEE Main 2012 Physics question
Water is flowing through a horizontal tube having cross-sectional areas of its two ends being A and A′ such that the ratio A/A′ is 5 . If the pressure difference of water between the two ends is , the velocity of water with which it enters the tube will be (neglect gravity effects)
Answer: (1)
Solution
Continuity: v′ = 5v. Bernoulli: \fracv^2)$ =
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