If the line y = mx + 1 meets the circle x^2 + y^2 + 3x = 0 in two points equidistant from and on opposite sides of x-axis, then

JEE Main 2012 Mathematics question

If the line y = mx + 1 meets the circle in two points equidistant from and on opposite sides of x-axis, then

(1)3m + 2 = 0
(2)3m − 2 = 0Correct
(3)2m + 3 = 0
(4)2m − 3 = 0

Answer: (2)

Solution

The midpoint of the chord then lies on the x-axis, at the line's x-intercept . The chord's midpoint is the foot of the perpendicular from the centre ; the

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Question ID VK-103603