JEE Main 2013 Mathematics question

Not in JEE syllabus

Consider : Statement - I : (p ∧ ~q) ∧ (~p ∧ q) is a fallacy. Statement - II : (p → q) ↔ (~q → ~p) is a tautology.

(1)Statement - I is true; statement - II is false.
(2)Statement - I is false; Statement -II is true.
(3)Statement - I true; Statement -II true; Statement -II is a correct explanation for Statement - I.
(4)Statement - I is true; Statement - II is true; Statement - II is not a correct explanation for Statement - I.Correct

Answer: (4)

Solution

Statement I requires p ∧ ~p, which is never true — a fallacy (true). Statement II: an implication is

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Question ID VK-103879