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JEE Main 2013 Physics question

PhysicsOscillationsJEE Main 2013

Two springs of force constants 300 N/m (Spring A) and 400 N/m (Spring B) are joined together in series. The combination is compressed by 8.75 cm. The ratio of energy stored in A and B is . Then is equal to:

Answer: (1)

Solution

In series both springs carry the same force F, and . So

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Question ID VK-103896