JEE Main 2013 Chemistry question
Given Reaction Energy Change (in kJ): : 161; : 520; : 77; : (Electron gain enthalpy); : −1047; : −617. Based on data provided, the value of electron gain enthalpy of fluorine would be :
Answer: (3)
Solution
Born–Haber cycle: $-617 = 161 + 520 + 77 + Δ_{eg}H + (-1047)
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