JEE Main 2013 Physics question
A 70 kg man leaps vertically into the air from a crouching position. To take the leap the man pushes the ground with a constant force F to raise himself. The center of gravity rises by 0.5 m before he leaps. After the leap the c.g. rises by another 1 m. The maximum power delivered by the muscles is : (Take )
Answer: (2)
Solution
After take-off the c.g. rises 1 m, so the take-off speed is m/s. During the 0.5 m push the c.g. accelerates uniformly: m/s², so the net accelerating
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