Test SeriesFree PYQsExamsPricing

JEE Main 2013 Chemistry question

ChemistryChemical Bonding and Molecular StructureJEE Main 2013

Bond distance in HF is m. Dipole moment of HF is Cm. The percentage ionic character in HF will be : (electron charge C )

Answer: (4)

Solution

A fully ionic HF would have C m.

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-104109