JEE Main 2013 Chemistry question

Given : V, V, V, V. The correct order of reducing power of the species and will be:

• (1)Mn^{2+} < Cl^- < Cr^{3+} < CrCorrect
• (2)Mn^{2+} < Cr^{3+} < Cl^- < Cr
• (3)Cr^{3+} < Cl^- < Mn^{2+} < Cr
• (4)Cr^{3+} < Cl^- < Cr < Mn^{2+}