JEE Main 2013 Mathematics question
If the extremities of the base of an isosceles triangle are the points (2a, 0) and (0, a) and the equation of one of the sides is x = 2a, then the area of the triangle, in square units, is :
Answer: (2)
Solution
The side x = 2a passes through the base vertex (2a, 0), so the apex is C(2a, t). Equal sides: and ; $ = + - 2at + ⇒
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