JEE Main 2013 Physics question
The surface charge density of a thin charged disc of radius R is σ. The value of the electric field at the centre of the disc is . With respect to the field at the centre, the electric field along the axis at a distance R from the centre of the disc:
Answer: (1)
Solution
On the axis, . At x = R: \frac{σ}{2ε_0}$[1 -
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