JEE Main 2014 Physics question
The position of a projectile launched from the origin at t = 0 is given by m at t = 2 s. If the projectile was launched at an angle θ from the horizontal, then θ is (take g = 10 m).
Answer: (3)
Solution
Horizontally, . Vertically, \sin\frac$12(10)(4) = 50 ⇒
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