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JEE Main 2014 Chemistry question

ChemistryThermodynamicsJEE Main 2014

The standard enthalpy of formation of is −46.0 kJ/mol. If bond enthalpy of is −436 kJ/mol and that of is −712 kJ/mol, the average bond enthalpy of N − H bond in is :

Answer: (4)

Solution

For : , where x is the N–H bond enthalpy magnitude. So $-46 = 356 + 654 - 3x

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Question ID VK-104383