JEE Main 2014 Chemistry question

The gas liberated by the electrolysis of Dipotassium succinate solution is:

Answer: (3)

Solution

This is Kolbe's electrolysis. At the anode the dicarboxylate ^-OOC-CH_2-CH_2-COO^- loses two electrons and both carboxylate groups

Create a free account to read the complete working, and practise questions like this in a timed test.

Question ID VK-104478