JEE Main 2014 Physics question

At room temperature a diatomic gas is found to have an r.m.s. speed of 1930 m. The gas is:

Answer: (1)

Solution

From with T = 300 K, \frac{3RT}{v^2}\frac{3(8.314)(300)}{(1930)^2}$ =

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Question ID VK-104537