JEE Main 2014 Chemistry question
The amount of formed upon mixing 100 mL of 20.8% solution with 50 mL of 9.8% solution will be: (Ba = 137, Cl = 35.5, S = 32, H = 1 and O = 16)
Answer: (2)
Solution
100 mL of 20.8% contains 20.8 g, and , so 0.1 mol. 50 mL of 9.8% contains 4.9 g, and , so 0.05 mol. The reaction is 1
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