JEE Advanced 2026 Chemistry question
In a solvent S, a compound B is partially dissociated into C and D as given below:
B 2C+2D
B, C and D are non-volatile in nature. The molar mass of B is times the molar mass of S. The standard boiling point and the standard enthalpy of vaporization of S are and , respectively ( is the gas constant in ). A solution of B in S with an initial concentration of B as (mass/mass) has a boiling point of at bar pressure. In this solution, the mole percent of B that has been dissociated is .
Answer: 33.17
Solution
**Step 1 — ebullioscopic constant of S.** Let be the molar mass of S in . With K and ,
===16M\ K kg mol^{-1}.
**Step 2 — molality.** The molar mass
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