NEET 2026 Physics question
Consider the following nuclear reaction Take masses of U, Th and He as 238.050 u, 234.043 u and 4.003 u, respectively. The value for the reaction, in keV, is: [Given: 1 u = 931.5 MeV c]
Answer: (1)
Solution
Mass defect u. c^2$=0.004×931.5\ MeV=3.726\
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