JEE Advanced Mathematics question
If are four numbers such that the first three are in AP while the last three are in HP then
Answer: (A)
Solution
AP: . HP: c = \dfrac{2bd}{b + d} \Rightarrow bc + cd = 2bd = (a + c)d = ad + cd. Cancelling : .
If are four numbers such that the first three are in AP while the last three are in HP then
AP: . HP: c = \dfrac{2bd}{b + d} \Rightarrow bc + cd = 2bd = (a + c)d = ad + cd. Cancelling : .