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JEE Advanced Mathematics question

MathematicsBasic Mathematics and LogarithmJEE Advanced

The solution set of is

Answer: (B)

Solution

We need . Since , multiply through by :

|x+1|+|x+1| |x|=|x+1|^2\ ⇒\ |x+1|Missing or unrecognized delimiter for \big\big(1+|x|-|x+1|Missing or unrecognized delimiter for \big\big)=0 .

- . - : by the triangle inequality with equality iff

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Question ID VK-107920