Test SeriesFree PYQsExamsPricing

JEE Advanced Mathematics question

MathematicsQuadratic Equations and InequalitiesJEE Advanced

If are in GP, where are positive, then the equation has

Answer: (B),(C)

Solution

Write , ( real; ). Then and

D=-4ac=-3ac<0\ ⇒\ imaginary roots.

Moreover ax^2+arx+ar^2=a(x^2+rx+r^2)=a(x-r\omega)(x-r\omega^2), so the roots are

See the full step-by-step solution

Create a free account to read the complete working (3 steps), and practise questions like this in a timed test.

Create a free account

Question ID VK-108009