JEE Advanced Mathematics question

The number of ways to give 16 different things to three persons A, B, C so that B gets 1 more than A and C gets 2 more than B, is

Answer: (A)

Solution

Let A get things. Then B gets and C gets .

x+(x+1)+(x+3)=16⇒ 3x=12⇒ x=4,

so A, B, C get 4, 5, 7 things respect

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Question ID VK-108213