JEE Advanced Mathematics question
The total number of ways in which a beggar can be given at least one rupee from four 25-paisa coins, three 50-paisa coins and 2 one-rupee coins, is
Answer: (A)
Solution
Coins of the same denomination are identical. Let be the numbers of 25 p, 50 p and ₹1 coins given: , , , so selections in all. Remove those worth less than ₹1 (100 p): then and , i.e. : - : (4 selections;
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