JEE Advanced Mathematics question
The determinant
\begin{vmatrix} xp+y & x & y \\ yp+z & y & z \\ 0 & xp+y & yp+z \end{vmatrix}=0
for all if
Answer: (B)
Solution
Apply : - row 1: - row 2: - row 3: 0 - p(xp+y) - (yp+z) = -(xp^2 + 2yp + z)
Δ = \begin{vmatrix} 0 & x & y \\ 0 & y & z \\ -(xp^2+2yp+z) & xp+y & yp+z \end{vmatrix} =
See the full step-by-step solution
Create a free account to read the complete working (3 steps), and practise questions like this in a timed test.
Create a free account