Let 0 2 and x=X +Y , y=X -Y such that x^2+4xy+y^2=aX^2+bY^2, where a,b are constants. Then

JEE Advanced Mathematics question

Let and , such that , where are constants. Then

Answer: (B),(C)

+=+, xy=-θθ-XY(θ-θ).

+4xy+=(1+22θ+(1-22θ-42θ XY.

For this to equal id

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Question ID VK-108518