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JEE Advanced Mathematics question

MathematicsTrigonometric EquationsJEE Advanced

Not in JEE Main syllabus

The number of values of that satisfy is

Answer: (D)

Solution

Need . Multiplying by :

x-1=2x=2-2x\ ⇒\ 2x+ x-3=0\ ⇒\ (2 x+3)( x-1)=0 .

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Question ID VK-108539