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JEE Advanced Mathematics question

MathematicsTrigonometric EquationsJEE Advanced

Not in JEE Main syllabus

If then the number of solutions of is

Answer: (B)

Solution

For both logarithms to be defined we need and , i.e. lies in the first quadrant (mod ). Then

x + x = 1 ⇒ ( x x) = 1 ⇒ x x = Missing argument for \tfrac\tfrac12 ⇒ 2x = 1.

So $2x =

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Question ID VK-108657