Test SeriesFree PYQsExamsPricing

JEE Advanced Mathematics question

MathematicsBasic Mathematics and LogarithmJEE Advanced

If , , then the number of solutions of is

Answer: (D)

Solution

Base , so the inequality is (this also ensures the argument is positive). Since , write

x + 2Missing argument for \sqrt\sqrt2 x = 3(Missing argument for \tfrac\tfrac13 x + x) = 3(x+α), α = Missing argument for \tfrac\tfrac13,\ α =

See the full step-by-step solution

Create a free account to read the complete working (5 steps), and practise questions like this in a timed test.

Create a free account

Question ID VK-108667