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JEE Advanced Mathematics question

MathematicsCircleJEE Advanced

A circle touches the -axis at and has an intercept of 4 units on the positive side of the -axis. Then the equation of the circle is

Answer: (A)

Solution

Since the circle touches the -axis at , its centre is and its radius is :

(x- + (y- = \ ⇒\ + - 2hx - 4y + 4 = 0.

Putting gives . The intercept is , so $

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Question ID VK-108897