The equation of a chord of the circle x^2 + y^2 - 4x = 0 which is bisected at the point (1, 1) is

JEE Advanced Mathematics question

The equation of a chord of the circle which is bisected at the point is

Answer: (D)

Chord with mid-point : . Here and (so is inside):

x+y-2x-2=-2 ⇒ -x+y=0

Create a free account to read the complete working (3 steps), and practise questions like this in a timed test.

Question ID VK-108943