The equations of two circles are x^2 + y^2 + 2 x + 5 = 0 and x^2 + y^2 + 2 y + 5 = 0. P is any point on the...

Question

The equations of two circles are x^2 + y^2 + 2 x + 5 = 0 and x^2 + y^2 + 2 y + 5 = 0. P is any point on the line x - y = 0. If PA and PB are the lengths of the tangents from P to the two circles and PA = 3 then PB is equal to

Accepted Answer

(C)

JEE Advanced Mathematics question

Solution

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