The equation of the tangent to the ellipse 4x^2+3y^2=12 at the point whose eccentric angle is 4 is

JEE Advanced Mathematics question

The equation of the tangent to the ellipse at the point whose eccentric angle is is

Answer: (B)

, so the point with eccentric angle is . At it is .

Tangent: $

Create a free account to read the complete working (3 steps), and practise questions like this in a timed test.

Question ID VK-109085