JEE Advanced Mathematics question
Let be a function such that , where is a constant. The value of for which is an onto function, is
- (A)
- (B)
- (C)Correct
- (D)none of these
Answer: (C)
Solution
is increasing and maps onto . So the range of is exactly iff the range of is exactly . Now
g(x) = (x + Missing argument for \tfrac\tfrac + k - Missing argument for \tfrac\tfrac14,
so the range of is \frac$14,
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Question ID VK-109154