JEE Advanced Mathematics question

MathematicsQuadratic Equations and InequalitiesJEE Advanced

Let be a function such that , where is a constant. The value of for which is an onto function, is

Answer: (C)

Solution

is increasing and maps onto . So the range of is exactly iff the range of is exactly . Now

g(x) = (x + Missing argument for \tfrac\tfrac + k - Missing argument for \tfrac\tfrac14,

so the range of is \frac$14,

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Question ID VK-109154